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-5y^2+12y-7=0
a = -5; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·(-5)·(-7)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2}{2*-5}=\frac{-14}{-10} =1+2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2}{2*-5}=\frac{-10}{-10} =1 $
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